The law of constant composition - 1 | Ionic and Covalent Compounds

General Chemistry 1 - The law of constant composition - 1

Find the percent composition of calcium hydroxide and calcium carbonate.

Calcium hydroxide = Ca(OH)2
MCa(OH)2 = 74.09 g.mol-1
MCa = 40.08 g.mol-1
MO = 16.0 g.mol-1
MH = 1.01 g.mol-1

% Ca = 54.1%, % O = 43.2%, % H = 2.73%
 

Calcium hydroxide = CaCO3
MCaCO3 = 100.1 g.mol-1
MCa = 40.08 g.mol-1
MO = 16.0 g.mol-1
MC = 12.0 g.mol-1

% Ca = 40.0%, % O = 48.0%, % C = 12.0%