Exercise 12 | Lewis Formulas
Balance the following reaction and calculate its change in enthalpy ΔH0.
C6H5COOH + O2 → CO2 + H2O
Data:
Bond energy (BE):
H-H = 436 kJ.mol-1
C-H = 413 kJ.mol-1
C-C = 347 kJ.mol-1
C=C = 607 kJ.mol-1
C-0 = 358 kJ.mol-1
C=0 = 805 kJ.mol-1
O-O = 204 kJ.mol-1
O=O = 498 kJ.mol-1
O-H = 464 kJ.mol-1
2 C6H5COOH + 15 O2 → 14 CO2 + 6 H2O
ΔH0 = 6 BE (C=C) + 8 BE (C-C) + 2 BE (C=O) + 2 BE (C-O) + 2 BE (O-H) + 10 BE (C-H) + 15 BE (O=O)
- 28 BE (C=O) – 12 BE (O-H)
= -6836 kJ.mol-1