What is the molarity M of a solution containing 32.1 grams of solute with a molar mass M = 24.0 g.mol^-1 in 450 mL of solution?

Question

| General Chemistry 2

Accepted Answer

n = $\frac{m}{M}$ and n = M x V

⇒ M x V =

\frac{m}{M}

⇒ M =

\frac{m}{M \times V}

⇒ M =

\frac{32.1}{24.0 \times 0.450}

= 2.97 mol.L^-1

Molarity vs. molality - 3 | Chemical Calculations for Solutions