# Molarity vs. molality - 3 | Chemical Calculations for Solutions

What is the molarity M of a solution containing 32.1 grams of solute with a molar mass M = 24.0 g.mol-1 in 450 mL of solution?

n = $\frac{\mathrm{m}}{\mathrm{M}}$   and   n = M x V

M x V = $\frac{\mathrm{m}}{\mathrm{M}}$

M =

M =  = 2.97 mol.L-1