Exercise 7 | Chemical Calculations for Solutions

In a titration experiment, it was found that 22.4 mL of 0.250M NaOH (aq) is required to neutralize 25.0 mL of H2SO4 (aq).

Write the equation of this reaction and calculate the concentration of the acidic solution.

Equation: 2 NaOH (aq) + H2SO4 (aq) → Na2SO4 (aq) + 2 H2O (l)


According to the equation: 2 moles of NaOH are required to neutralized 1 mole of H2SO4

⇒ when the endpoint of the neutralization is reached: nNaOH = 2 nH2SO4

⇒ MNaOH x VNaOH = 2 x MH2SO4 x VH2SO4

MH2SO4 = MNaOH × VNaOH2 VH2SO4

MH2SO4 = 0.250 × 22.42 × 25.0 = 0.112 M