Acid-base titrations - 1 | Chemical Calculations for Solutions

Equation: 2 NaOH (aq) + H₂SO₄ (aq) → Na₂SO₄ (aq) + 2 H₂O (l)

According to the equation: 2 moles of NaOH are required to neutralized 1 mole of H₂SO₄

⇒ when the endpoint of the neutralization is reached: n_NaOH = 2 n_H2SO4

⇒ M_NaOH x V_NaOH = 2 x M_H2SO4 x V_H2SO4

⇒ M_H2SO4 = $\frac{M_{NaOH} \times {\mathrm{V}}_{\mathrm{NaOH}}}{2 {\mathrm{V}}_{\mathrm{H}2\mathrm{SO}4}}$

⇒ M_H2SO4 = $\frac{0.250 \times 22.4}{2 \times 25.0}$ = 0.112 M