Acid-base titrations - 2 | Chemical Calculations for Solutions
General Chemistry 2 - Acid-base titrations - 2
In a titration experiment, it was found that 63.0 mL of 0.350 M KOH (aq) is required to neutralize 175 mL of HCl (aq).
What is the concentration of the HCl solution?
Equation: KOH (aq) + HCl (aq) → KCl (aq) + H2O (l)
According to the equation: 1 mole of KOH is required to neutralized 1 mole of HCl
⇒ when the endpoint of the neutralization is reached: nKOH = nHCl
⇒ MKOH x VKOH = MHCl x VHCl
⇒ MHCl =
⇒ MHCl = = 0.126 M