Exercise 5 | Chemical Equilibrium

Reaction 1:

4 NO (g) + 2 O(g)  4 NO2(g)     [KP1 = 1.22 atm-1]


Reaction 2:

2 NO(g)  2 NO (g) + O(g)     [KP2 = ???]


Determine the value of KP2

{4 NO (g) + 2 O(g)  4 NO(g)}    =   2 x {(2 NO (g) + O(g)  2 NO(g)}


Reaction 1 = 2 x (reverse of Reaction 2)

KP1 1KP22 

KP2  = 1KP1 = 9.06 x 10-1 atm1/2