Exercise 5 | Chemical Equilibrium

General Chemistry 3 - Exercise 5

Reaction 1:

4 NO (g) + 2 O2 (g) ⇄ 4 NO2(g)     [KP1 = 1.22 atm-1]


Reaction 2:

2 NO2 (g) ⇄ 2 NO (g) + O2 (g)     [KP2 = ???]


Determine the value of KP2

{4 NO (g) + 2 O2 (g) ⇄ 4 NO2 (g)}    =   2 x {(2 NO (g) + O2 (g) ⇄ 2 NO2 (g)}


Reaction 1 = 2 x (reverse of Reaction 2)

KP1 = 1KP22 

KP2  = 1KP1 = 9.06 x 10-1 atm1/2