Solubility and Precipitation Reactions | General Chemistry 3

Solubility and precipitation reactions are studied in this chapter: solubility, molar solubility, solubility product constant, calculations of solubility, precipitation of ionic compounds, reaction quotient, factors affecting solubility, common ion effect, fractional precipitation, qualitative analysis.

Solubility Equilibria

Solubility (S):

Solubility refers to the maximum amount of a substance that can dissolve in a solvent to form a saturated solution, typically expressed in g.L-1. At saturation, a dynamic equilibrium is established between the undissolved solid and its dissolved ions, meaning that the rate of dissolution equals the rate of precipitation.

 

Molar solubility (s):

Molar solubility is the amount of a compound that dissolves in 1 liter of solution, expressed in mol.L-1, to form a saturated solution. The relationship between solubility and molar solubility is given by:
 

s x M

S = solubility (in g.L-1)
s = molar solubility (in mol.L-1)
M = molar mass of the salt (in g.mol-1)


 

Solubility product constant:

The solubility product constant (Ksp) is the equilibrium constant for the dissolution reaction of a sparingly soluble salt. It represents the product of the molar concentrations of the dissolved ions, each raised to the power of its stoichiometric coefficient.

For a general salt MmXx​, that dissociates as follows:

MmXx (s)  m Mn+ (aq) + x Xy- (aq)

The solubility product constant is expressed as:
 

Ksp = [Mn+]m [Xy-]x

Ksp = solubility product constant
[Mn+] = concentration of the ion Mn+ in solution (in M)
[Xy-] = concentration of the ion Xy- in solution (in M)
m and x = stoichiometric coefficient of Mn+ and Xy-

 

Since the solid phase of the salt is considered pure, its concentration is treated as 1 and does not appear in the Ksp expression.

 

  • AgBr (s)  Ag+ (aq) + Br- (aq)
    Ksp = [Ag+] [Br-]
  • Ag2CO3 (s)  2 Ag+ (aq) + CO32- (aq)
    Ksp = [Ag+]2 [CO32-]

Calculations of Solubility

General steps for calculating molar solubility:

  1. Write the balanced dissociation equation for the salt.
  2. Define molar solubility s, where s moles of the salt dissolve per liter to form a saturated solution.
  3. Set up the Ksp expression by substituting the ion concentrations in terms of s into the Ksp expression.
  4. Solve for s by rearranging the Ksp expression.
  5. Calculate solubility S in g.L-1, if required, using the molar mass of the salt: S = s x M.

 

Solubility of AgBr:

  • Dissociation: AgBr (s) Ag+ (aq) + Br- (aq)
  • Since [Ag+] = [Br-] = s, we have:
    Ksp = [Ag+] [Br-] = s2 ⇒ sKsp
  • Solubility S in g.L-1 = s x MAgBr = Ksp x MAgBr

 

Expressions of the solubility may be more complex, involving s3 or higher powers, depending on the stoichiometry.
 

Solubility of MgF2:

  • Dissociation: MgF2 (s) Mg2+ (aq) + 2 F- (aq)
  •   MgF2 (s) Mg2+ (aq) 2 F- (aq)
    Initial Concentration (M)   0 0
    Equilibrium Conc. (M)   s 2s
  • Ksp = [Mg2+] [F-]2 = s (2s)2 = 4s3
    s = Ksp43

Precipitation of Ionic Compounds

Reaction quotient (Q):

The reaction quotient Q is calculated in the same way as the solubility product constant Ksp​, but it uses the current ion concentrations rather than the concentrations at equilibrium.
 

Predicting precipitation:

By comparing Q to Ksp, we can determine whether a precipitate will form:

  • If Q > Ksp: The solution is supersaturated, and a precipitate will form as excess ions combine until Q decreases to match Ksp.
  • If Q < Ksp: The solution is unsaturated, so no precipitation occurs; additional solute can dissolve until Q increases to Ksp​.
  • If Q = Ksp: The system is at equilibrium; the solution is saturated with no net precipitation or dissolution.


When equilibrium is disturbed:

If the equilibrium is disturbed by concentration changes, Q shifts accordingly:

  • If Q > Ksp: More precipitate forms to reduce ion concentrations until Q = Ksp.
  • If Q < Ksp: The precipitate dissolves, increasing ion concentrations until Q = Ksp or the precipitate fully dissolves.

Factors Affecting Solubility

The common ion effect:

  • A common ion is an ion that is already present in the solution before the addition of a new compound containing the same ion.
  • The common ion effect refers to the decrease in solubility of an ionic solid when a common ion is present, as the equilibrium shifts to favor the undissolved solid.
     
  • Consider the solubility of CaF2​ in water:
    CaF2 ​(s) ⇌ Ca2+ (aq) + 2 F (aq)
  • If NaF (which provides additional F ions) is added to the solution, the increased F concentration shifts the equilibrium to the left, reducing the solubility of CaF2​.

 

The pH of the solution:

The solubility of compounds containing basic anions (e.g., OH, CO32−​, PO43−​) increases in acidic solutions. In these cases, H+ ions react with the anions, reducing their concentration and shifting the equilibrium to dissolve more of the compound.
 

  • Consider the solubility of CaCO3 in water:
    CaCO3​ (s) ⇌ Ca2+ (aq) + CO32−​ (aq)
  • In an acidic solution, CO32−​ ions react with H+ to form HCO3− or H2CO3​, lowering the CO32− concentration. This shift increases the solubility of CaCO3​ by driving the equilibrium to the right.

 

The formation of complex ions:

  •  A complex ion is a metal ion with small molecules or ions (ligands) attached to it.
  • Some metal ions form complex ions in solution, increasing their solubility. When a ligand (like NH3 or CN) binds to a metal ion, it forms a soluble complex, shifting the equilibrium to dissolve more of the compound.
     
  • Consider the solubility of AgCl in water:
    AgCl (s) ⇌ Ag+ (aq) + Cl (aq)
  • If NH3​ is added, it forms a complex ion with Ag+:
    Ag+ (aq) + 2 NH3 (aq) → [Ag(NH3)2]+ (aq)
  • This reaction reduces the Ag+ concentration, shifting the equilibrium to dissolve more AgCl ⇒ The formation of [Ag(NH3)2]+ increases the solubility of AgCl in the presence of NH3​. 

 

Amphoterism:

Amphoteric substances can act as either acids or bases, depending on the pH of the solution. Some metal hydroxides, such as Al(OH)3​, Zn(OH)2​, and Cr(OH)3, are amphoteric and dissolve in both acidic and basic environments due to their ability to react with both H+ and OH ions.
 

Amphoteric behavior allows Al(OH)3 to dissolve in both acidic and basic solutions, enhancing its solubility depending on the pH:

  • In acidic solutions, it dissolves by reacting with H+:
    Al(OH)(s) + 3 H+ (aq) → Al3+ (aq) + 3 H2O (l)
  • In basic solutions, it dissolves by forming a soluble hydroxy complex:
    Al(OH)3 (s) + OH (aq) → [Al(OH)4] (aq)

Fractional Precipitation

Fractional precipitation:

Fractional precipitation is a method used to separate ions in a solution by adding a reagent that selectively causes one ion to precipitate while leaving others in solution. This technique is based on differences in the solubility products (Ksp​) of the ionic compounds formed, allowing for the targeted removal of specific ions.
 

  • Separation of Cl and SO42−​ by addition of Ba(NO3)2:

In a solution containing both Cl and SO42−​ ions, adding Ba(NO3)2 selectively precipitates SO42−​ as BaSO4​ due to its low Ksp​ ⇒ BaSO4​ precipitates first, leaving Cl in solution, as BaCl2 is more soluble. Filtering out the BaSO4 precipitate effectively separates the two ions.
 

  • Separation of Ag+ and Zn2+ by addition of dilute HCl:

In a solution containing Ag+ and Zn2+ ions, adding dilute HCl selectively precipitates Ag+ as AgCl due to its low Ksp​ ⇒ ZnCl2​ remains soluble, so Zn2+ stays in solution. Filtering out the AgCl precipitate leaves Zn2+ ions in the solution, effectively separating the two cations.

 

Steps for fractional precipitation:

  1. Identify the Ksp​ values of possible precipitates. Ions with lower Ksp​ values will precipitate first, as they reach saturation at lower ion concentrations.
  2. Add a precipitating agent to the solution gradually. As the reagent concentration increases, the ion with the lowest Ksp​ reaches its threshold for precipitation first.
  3. Monitor the reaction quotient Q in relation to Ksp​ for each ion. Precipitation occurs when Q = Ksp for a particular ion, allowing for selective separation based on solubility.

Qualitative Analysis

Qualitative analysis:

Qualitative analysis is a procedure for identifying the ions present in an unknown solution. Specific chemical tests identify each ion, but interference between ions can complicate testing. Therefore, ions are first separated into groups by selective precipitation. In the traditional qualitative analysis scheme for metal cations, about 20 cations are initially divided into 5 groups.
 

The 5 groups of metal cations:

Metal cations are categorized into 5 groups based on their behavior in qualitative analysis. Each group precipitates under unique conditions, allowing selective separation:

  • Group 1: Includes Ag+, Pb2+, and Hg22+, which precipitate as chlorides when dilute HCl is added.
  • Group 2: Includes Pb2+, Cu2+, Hg2+, Cd2+, Bi3+, and Sn4+, which form insoluble sulfides in acidic conditions with hydrogen sulfide (H2S).
  • Group 3: Includes Mn2+, Fe3+, Co2+, Ni2+, Zn2+, Al3+, and Cr3+, which precipitate as hydroxides or sulfides in basic conditions (using NHwith H2S).
  • Group 4: Includes Ca2+ and Ba2+, which precipitate as carbonates when (NH4)2CO3 is added.
  • Group 5: Includes Na+, K+, and Mg2+, which do not precipitate under conditions used for Groups 1-4 and remain in solution. Alkali metal ions are often identified by the characteristic colors they produce in a Bunsen flame.

 

Flowchart for the separation of cations:

  • Step 1: Add dilute HCl to the sample ⇒ Group 1 precipitates (AgCl, Hg2Cl2, PbCl2).
  • Step 2: Add H2S ⇒ Group 2 precipitates (PbS, CuS, HgS, CdS, Bi2S3, SnS2).
  • Step 3: Add NH3 ⇒ Group 3 precipitates (MnS, FeS, CoS, NiS, ZnS, Al(OH)3, Cr(OH)3).
  • Step 4: Add (NH4)2CO3 ⇒ Group 4 precipitates (CaCO3, BaCO3).
  • Remaining ions in solution: Group 5 cations (Na+, K+, Mg2+) stay in solution and can be identified by flame tests or further testing.

Check your knowledge about this Chapter

  • Solubility equilibrium refers to the dynamic equilibrium that exists in a saturated solution when the rate of dissolution of a solute is equal to the rate of precipitation. In this state, the concentration of dissolved species remains constant.
  • A chemical equation representing solubility equilibrium can be written for a sparingly soluble salt, like silver chloride, as follows:
    AgCl (s) ⇌ Ag(aq) + Cl- (aq)
    The double arrow indicates that the dissolution of the solid into its ions (rightward direction) and the precipitation of the ions to form the solid (leftward direction) are occurring at the same rate.

The solubility product constant (Ksp) is a measure of the extent to which a compound can dissociate into its constituent ions in solution. For a sparingly soluble compound AB that dissociates into A⁺ and B⁻ ions, represented as AB(s) ⇌ A+ (aq) + B- (aq), the Ksp is defined by the product of the molar concentrations of the ions at equilibrium, [A+][B-], raised to the power of their respective stoichiometric coefficients in the balanced equation.

The higher the Ksp value, the more soluble the compound is in water. The Ksp value is useful in predicting whether a precipitate will form when solutions of two ionic compounds are mixed, based on whether the ionic product (the actual product of the ions' concentrations) exceeds the Ksp.

The common ion effect refers to the decrease in solubility of an ionic compound when a salt containing a common ion is added to the solution. It occurs because the addition of a common ion shifts the equilibrium of the dissolution process in the direction of forming more solid, as predicted by Le Chatelier's principle. This results in a lower concentration of the solute ions in the solution, therefore reducing its solubility.

The molar solubility of a compound can be determined from its solubility product constant (Ksp) by setting up an equilibrium expression based on the dissolution equation.

For example, for a salt AB that dissociates in water as A+ and B-, Ksp = [A+][B-], where [A+] and [B-] are the molar concentrations of the ions at equilibrium. If AB has a 1:1 stoichiometry, the molar solubility s is simply the square root of Ksp, since s = [A+] = [B-]. For salts with different stoichiometries, the equilibrium expression will be different, and s should be calculated according to the stoichiometry.

To write the solubility equilibrium expression for a sparingly soluble salt, you must first write the balanced chemical equation for the dissolution of the salt. Next, express the equilibrium constant (Ksp) for the dissolution process, which is called the solubility product constant. This involves writing the concentrations of the ions produced at equilibrium raised to the power of their coefficients in the balanced equation, omitting the concentration of the solid salt itself as it doesn't appear in the expression for Ksp.

The difference between a precipitate and a soluble compound lies in their solubility in a particular solvent, usually water.

  • A precipitate is an insoluble compound that forms when the concentration of its ions exceeds their solubility product, leading to a solid deposit settling out of the solution.
  • On the other hand, a soluble compound has high solubility in the solvent and remains dissolved at a given temperature and pressure, maintaining a uniform mixture.

Fractional precipitation is a process used to separate ions in a mixture by selectively precipitating one ion at a time. By carefully adjusting the concentration of precipitating agents and controlling the pH of the solution, certain ions can be made to form insoluble compounds that fall out of solution while others remain dissolved. This relies on the fact that different ionic compounds have different solubility products (Ksp), meaning they have different solubilities at a given temperature and pH. By exploiting these differences, chemists can sequentially remove specific ions from a mixture. This technique is particularly useful in qualitative chemical analysis and in the purification of compounds.

Understanding precipitation reactions is vital in qualitative analysis as it allows chemists to identify the presence of specific ions in a mixture. When a reagent is added that forms an insoluble compound with a particular ion, a precipitate will form, signaling the presence of that ion. This process is key to separating and identifying cations and anions in a sample, and can also be used to purify substances by removing unwanted ions.

Complex ion formation and chelation can greatly increase the solubility of a compound. This happens because a metal ion in solution can bond with one or more ligands to form a complex ion, which is often more soluble than the simple metal ion or its salts.

Chelation involves a single ligand that forms multiple bonds to the metal ion, creating very stable complex ions. The increased stability of these complexes is due to the chelating ligands spatially encircling the metal ion, hence they tend to be more soluble in water, which can help to dissolve otherwise insoluble metal salts by forming these soluble complex ions.