Exercise 5 | Solubility and Precipitation Reactions
General Chemistry 3 - Exercise 5
Calculate the solubility of Ag2CO3 (s) in g.L-1 in an aqueous solution that is 0.10 M in AgNO3 (aq).
Data: Ksp (Ag2CO3) = 8.5 x 10-12 M 3
Chemical equation:
Ag2CO3 (s) 2 Ag+ (aq) + CO32- (aq)
At equilibrium:
[Ag+] = 0.10 + 2s
[CO32-] = s
Ksp = [Ag+]2[CO32-] = (0.10+2s)2 x s
Hypothesis 2s << 0.10
⇒ Ksp = 0.102 x s
⇒ s = 8.5 x 10-10 M (the hypothesis is verified)
S = solubility of Ag2CO3 (s) in g.L-1 = s x MAg2CO3
⇒ S = 2.3 x 10-7 g.L-1