Exercise 3 | Solubility and Precipitation Reactions

s (solubility of TlCl (s) in M) = S (solubility in g.L^-1) / M_TlCl

⇒ s = 1.4 x 10^-2 M

Chemical equation:

TlCl (s) $\rightleftarrows$ Tl⁺ (aq) + Cl^- (aq)

Pure water: the only source of Tl⁺ and Cl^- is TlCl

From the reaction stoichiometry: [Tl⁺] = [Cl^-]

s = [Tl⁺] = [Cl^-]

K_sp = [Tl⁺][Cl^-]

K_sp = s²

⇒ K_sp = 1.9 x 10^-4 M ²