# Quiz | Solubility and Precipitation Reactions

1

What is the solubility-product constant expression for the dissolution of tin(II) hydroxide?

$\left[{\mathrm{Sn}}^{2+}\right]{\left[{\mathrm{HO}}^{-}\right]}^{2}$

$\frac{1}{\left[{\mathrm{Sn}}^{2+}\right]{\left[{\mathrm{HO}}^{-}\right]}^{2}}$

${\left[{\mathrm{Sn}}^{2+}\right]}^{2}\left[{\mathrm{HO}}^{-}\right]$

$\frac{1}{{\left[{\mathrm{Sn}}^{2+}\right]}^{2}\left[{\mathrm{HO}}^{-}\right]}$

2

What is the molar solubility of BaCO3?

s = Ksp1/3

s = Ksp1/2

s = Ksp2

s = ( ${\mathrm{K}}_{\mathrm{sp}}}{4}$ )1/3

3

What is the molar solubility of Ca3(PO4)2?

s = Ksp1/5

s = ( ${\mathrm{K}}_{\mathrm{sp}}}{27}$ )1/5

s = ( ${\mathrm{K}}_{\mathrm{sp}}}{36}$ )1/5

s = ( ${\mathrm{K}}_{\mathrm{sp}}}{108}$ )1/5

4

In which conditions would Ag3PO4 be least soluble?

Pure water

0.1 M AgNO3

0.1 M HNO3

Solubility does not change

5

Which of the following sentences is incorrect?

The solubility of an ionic solid can be decreased by the formation of a soluble complex ion

The solubility of an ionic solid decreases when a common ion is present in solution

When equilibrium is disturbed and Qsp > Ksp, more precipitate forms until Qsp = Ksp

None of the above

6

Why Al(OH)3 is soluble in basic solution but insoluble in neutral solution?

Because of the common ion effect

Because of the acid-base neutralization

Because of the formation of a soluble hydroxy complex ion [Al(OH)4]-

Because of the solubility-product constant Ksp