Calculate the pH of a solution that is 0.200 M in ammonia NH₃ and 0.300 M in ammonium chloride NH₄Cl.

Data: Ka (NH₄⁺/NH₃) = 5.62 x 10^-10

Question

Calculate the pH of a solution that is 0.200 M in ammonia NH₃ and 0.300 M in ammonium chloride NH₄Cl.

Data: Ka (NH₄⁺/NH₃) = 5.62 x 10^-10

| General Chemistry 3

Accepted Answer

Henderson-Hasselbalch equation can be used:

pH = pKa + log $\frac{{[base]}_{0}}{{[acid]}_{0}}$

pH = -log (5.62 x 10^-10) + log

\frac{0.200}{0.300}

pH = 9.07

Exercise 1 | Buffers and Acid-Base Titrations