Exercise 1 | Colligative Properties of Solutions
General Chemistry 2 - Exercise 1
Calculate the molality and the mole fractions of a solution prepared by dissolving 23.0 g of fructose, C6H12O6 (s), in 500 mL of water.
Molality m (in mol.kg-1):
m =
nsolute = msolute / Msolute = msolute / (6 MC + 12 MH + 6 MO)
nsolute = 23.0 / 180.12 = 1.28 x 10-1 mol
msolution = Vsolution x d (with d = density of water = 1.00) = 0.500 kg
m = = 2.55 x 10-1 mol.kg-1
Mole Fraction:
xsolute =
nsolute = 23.0 / 180.12 = 1.28 x 10-1 mol
nsolution = 500 / 18.0 = 2.78 x 101 mol
xsolute = = 4.60 x 10-3