Exercise 5 | Thermochemistry

A substance increases in temperature by 167°C when a 2.56 kg sample of it absorbs 78.5 kJ of heat.

What is the specific heat capacity of the substance?

cS = $\frac{{\mathrm{c}}_{\mathrm{P}}}{\mathrm{m}}$ = $\frac{{\mathrm{q}}_{\mathrm{P}}}{\mathrm{m}∆\mathrm{T}}$

qP = energy added as heat (in J)

ΔT = change of temperature (in K)

m = mass (in g)

cS =  = 6.97 x 10-2 J.g-1.K-1