Exercise 4 | Electrochemistry
General Chemistry 3 - Exercise 4
Given that [Al3+] = 1.00 x 10-2 M, what is the reduction potential for the following half-reaction:
Al3+ (aq) + 3 e- → Al (s)?
Data: E0red [Al3+] = - 1.66 V at 25°C
Nernst equation:
At 25°C:
Ered = E0red – x ln Q = E0red – x ln Q
Ered = reduction potential (in V)
E0red = -1.66V
νe = stoichiometric coefficient of the electrons = 3
Q = reaction quotient = 1 / [Al3+]
Ered = E0red – x ln Q
Ered = - 1.66 + x ln 0.200
Ered = - 1.70 V