# Exercise 5 | Electrochemistry

E0cell = 0.47 V at 25°C for the following reaction:

Pb (s) + Cu2+ (aq) $⇄$ Pb2+ (aq) + Cu (s)

What is the value of the equilibrium constant?

Nernst equation at the equilibrium:

At 25°C:

Ecell = E0cell$\frac{0.02570}{{\mathrm{\nu }}_{\mathrm{e}}}$  ln K = 0   (equilibrium)

E0cell = standard cell voltage (in V)
νe = stoichiometric coefficient of the electrons = 2
K = equilibrium constant

E0cell$\frac{0.02570}{{\mathrm{\nu }}_{\mathrm{e}}}$ ln K = 0

K = exp

K = 7.7 x 1015