E⁰_cell = 0.47 V at 25°C for the following reaction:

Pb (s) + Cu²⁺ (aq) $⇄$ Pb²⁺ (aq) + Cu (s)
What is the value of the equilibrium constant?

Question

E⁰_cell = 0.47 V at 25°C for the following reaction:

Pb (s) + Cu²⁺ (aq)

⇄

Pb²⁺ (aq) + Cu (s)

What is the value of the equilibrium constant?

| General Chemistry 3

Accepted Answer

Nernst equation at the equilibrium:

At 25°C:

E_cell = E⁰_cell –

\frac{0.02570}{ν_{e}}

ln K = 0 (equilibrium)

E⁰_cell = standard cell voltage (in V) ν_e = stoichiometric coefficient of the electrons = 2 K = equilibrium constant

E⁰_cell –

\frac{0.02570}{ν_{e}}

ln K = 0

K = exp

(\frac{{E^{0}}_{cell} \times ν_{e}}{0.02570})

K = 7.7 x 10¹⁵

Exercise 5 | Electrochemistry