Stoichiometry - 4 | Chemical Calculations
General Chemistry 2 - Stoichiometry - 4
A 19.33 g sample of Mo2O3 is converted completely to another molybdenum oxide by reaction with dioxygen. The new oxide has a mass of 23.20 g. What is the empirical formula of this new oxide?
Sample 1:
nMo2O3 =
⇒ nMo2O3 =
nMo = 2 nMo2O3 = 1.572 x 10-1 mol
nO = 3 nMo2O3 = 2.358 x 10-1 mol
Sample 2:
Mo2O3 only reacts with O2 ⇒ no Mo atom is added
nO2 reacting =
nO2 =
nMo (sample 2) = nMo (sample 1) = 1.572 x 10-1 mol
nO (sample 2) = nO (sample 1) + nO2 = 2.358 x 10-1 + 2.419 x 10-1 = 4.777 x 10-1 mol
The empirical formula of the new oxide is MoO3