Molarity vs. molality - 3 | Chemical Calculations

Chapter 2 - Chemical Calculations

What is the molarity M of a solution containing 32.1 grams of solute with a molar mass M = 24.0 g.mol^-1 in 450 mL of solution?

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Solution

n =

\frac{m}{M}

and n = M x V

⇒ M x V = $\frac{m}{M}$

⇒ M = $\frac{m}{M \times V}$

⇒ M = $\frac{32.1}{24.0 \times 0.450}$ = 2.97 mol.L^-1

General Chemistry 2 - Molarity vs. molality - 3