Exercise 1 | Acids and Bases
General Chemistry 3 - Exercise 1
If Kw = 2.93 x 10-15 M 2 at 10°C, what is the pH of pure water at this temperature?
Kw = [H3O+][HO-]
Pure water: [H3O+] = [HO-]
Kw = [H3O+]2 = 2.93 x 10-15 M 2
⇒ [H3O+] = 5.41 x 10-8 M
⇒ pH = -log [H3O+] = 7.27