What mass of Na₂SO₄ is needed to make 3.2 L of 2.5 M solution?

Question

| General Chemistry 2

Accepted Answer

n_Na2SO4 = M_sol x V_sol and n_Na2SO4 = $\frac{m_{Na 2 SO 4}}{M_{Na 2 SO 4}}$

⇒

\frac{m_{Na 2 SO 4}}{M_{Na 2 SO 4}}

= M_sol x V_sol

⇒m_Na2SO4 = M_sol x V_solx M_Na2SO4

⇒m_Na2SO4 = 2.5 x 3.2 x (23 x 2 + 32 + 4 x 16) = 1.1 x 10³ g = 1.1 kg

Molarity vs. molality - 1 | Chemical Calculations for Solutions