Quiz | Chemical Calculations for Solutions

Solubility is the maximum quantity of solute dissolvable in a solvent at a particular temperature. A solid is more soluble at higher temperatures and in a solvent with similar types of intermolecular forces

Molarity M  =  $\frac{{\mathrm{n}}_{\mathrm{solute}}}{{\mathrm{V}}_{\mathrm{solution}}}$  =  $\frac{8}{2}$ =  4M

number of moles n_NaCl  =  M x V_solution  =  $\frac{{\mathrm{m}}_{\mathrm{NaCl}}}{{\mathrm{M}}_{\mathrm{NaCl}}}$  

⇒ m_NaCl  = M x V_solution x M_NaCl   with M_NaCl = molar mass of NaCl = M_Na + M_Cl = 23.0 + 35.4 = 58.4 g.mol^-1

⇒ m_NaCl  = 0.4 x 0.250 x 58.4 = 5.84 g

 In dilution, the amount of solute does not change: the number of moles are the same before and after dilution

In dilution, the amount of solute does not change: n₁ = n₂ ⇒ M₁ x V₁ = M₂ x V₂
2.0 x V₁ = 0.5 x 0.300 ⇒ V₁ = 0.075 L = 75 mL