Exercise 4 | Chemical Equilibrium
General Chemistry 2 - Exercise 4
For the equilibrium described by:
2 HgO (s) 2 Hg (l) + O2 (g) [KP = 12.0 atm at 850 K]
1) Find the relation between KP and KC.
2) Find the value of KC at this temperature.
1) KP = PO2 and KC = [O2]
⇒ KP = KC RT
2) KC =
with KP in Pa ⇒ 12.0 atm = 12.2 x 106 Pa
R = 8.314 J.mol-1.K-1
T in K
KC = = 1.73 x 103 mol.L-1