Exercise 5 | Chemical Equilibrium
General Chemistry 2 - Exercise 5
Reaction 1:
4 NO (g) + 2 O2 (g) 4 NO2(g) [KP1 = 1.22 atm-1]
Reaction 2:
2 NO2 (g) 2 NO (g) + O2 (g) [KP2 = ???]
Determine the value of KP2
{4 NO (g) + 2 O2 (g) 4 NO2 (g)} = 2 x {(2 NO (g) + O2 (g) 2 NO2 (g)}
Reaction 1 = 2 x (reverse of Reaction 2)
KP1 =
KP2 = = 9.06 x 10-1 atm1/2