C (s) + CO₂(g) $⇄$ 2 CO (g) [K_P = 1.00 atm]
Is the reaction at equilibrium if P_CO2 = 0.200 bar and P_CO = 0.650 bar?
If not, in what direction will the reaction proceed to attain equilibrium?

Question

C (s) + CO₂(g)

⇄

2 CO (g) [K_P = 1.00 atm]

Is the reaction at equilibrium if P_CO2 = 0.200 bar and P_CO = 0.650 bar?

If not, in what direction will the reaction proceed to attain equilibrium?

| General Chemistry 2

Accepted Answer

Let’s calculate the reaction quotient Q_C:

Q_C =

\frac{{P_{CO}}^{2}}{P_{{CO}_{2}}}

Q_C= 2.11 bar = 1.97 atm

Q_C > K_P

⇒ the reaction is not at the equilibrium

⇒ the reaction will move to the left

Exercise 8 | Chemical Equilibrium