Exercise 5 | Chemical Kinetics: Mechanisms
The rate of an elementary reaction has been studied as a function of temperature.
The following data were obtained for the rate constant:
Exp 1: T = 300K; k = 6.47 mol.L-1.s-1
Exp 2: T = 500K; k = 2.84 x 104 mol.L-1.s-1
Exp 3: T = 700K; k = 1.03 x 106 mol.L-1.s-1
Calculate the activation energy for the reaction.
k = Ae-Ea/RT
k2 / k1 = Ae-Ea/RT2 / Ae-Ea/RT1
⇒ k2 / k1 = e-Ea/RT2 + Ea/RT1
⇒ ln (k2 / k1) =
⇒ Ea = = 5.23 x 104 J = 52.3 kJ