Exercise 1 | Properties of Gases

Situation 1: V₁ = 95.0 dm³ and P₁ = 5.00 kPa = 5.00 x 10³ Pa

Situation 2: P₂ = 632 Pa

Boyle’s Law:

At constant temperature, P and V are inversely proportional:

P₁ V₁ = P₂ V₂

⇒ V₂ = $\frac{{\mathrm{P}}_1 {\mathrm{V}}_1}{{\mathrm{P}}_2}$

⇒ V₂ = $\frac{5.00 \times {10}^3 \times 95.0}{632}$

V₂ = 7.52 x 10² dm³ = 7.52 x 10² L