Oxidation Numbers - 2 | Chemical Reactions and Properties of Solutions

General Chemistry 2 - Oxidation Numbers - 2

Determine the oxidation number of the elements in each of the following compounds:

SF4, N2, Na2SO4 and MnO4-?

SF4 ⇒ 4 F- + Sx ⇒ SF4 is neutral: 0 = 4(-1) + x
oxidation states: S = +4 and F = -1


N2 ⇒ 2 N ⇒ oxidation state: N = 0


Na2SO4 ⇒ 2 Na+ + 4 O2- + Sx ⇒ Na2SO4 is neutral: 0 = 2(+1) + x + 4(-2)
oxidation states: Na = +1; S = +6 and O = -2


MnO4- ⇒ 4 O2- + Mnx ⇒ MnO4- is negatively charged: -1 = x + 4(-2)
oxidation states: Mn = +7  and O = -2