# Exercise 3 | Liquids and Solids

The relative humidity in a green house at 35.0°C is 88.5%.

Calculate the vapor pressure of water vapor in the greenhouse (in Pa).

Data: vapor pressure of water at 35.0°C = 41.2 mmHg  (1 mmHg = 1.33 x 10-1 kPa)

φ = $\frac{{\mathrm{P}}_{\mathrm{H}2\mathrm{O}}}{{{\mathrm{P}}^{0}}_{\mathrm{H}2\mathrm{O}}}$ x 100

PH2O = partial pressure of the water vapor in the greenhouse
P0H2O = equilibrium vapor pressure of water at the same temperature

P0H2O = 41.2 mmHg = 5.49 kPa
PH2O =   = 4.86 kPa = 4860 Pa