Calculate the mass of 3.12 x 10 22 formula units of aluminum chloride AlCl 3 . | General Chemistry 1

n AlCl3 = m AlCl 3 M AlCl 3 = N N A ⇒ m AlCl3 = x M AlCl3 = 6.91 g

Masses and mole number - 2 | The Periodic Table and Atoms

Chapter 3 - The Periodic Table and Atoms

Calculate the mass of 3.12 x 10²² formula units of aluminum chloride AlCl₃.

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Solution

n_AlCl3 =

\frac{m_{AlCl 3}}{M_{AlCl 3}}

\frac{N}{N_{A}}

⇒ m_AlCl3 = x M_AlCl3 = 6.91 g