Calculate the mass of 3.12 x 10²² formula units of aluminum chloride AlCl₃.

Question

| General Chemistry 1

Accepted Answer

n_AlCl3 =

\frac{m_{AlCl 3}}{M_{AlCl 3}}

=

\frac{N}{N_{A}}

⇒ m_AlCl3 = x M_AlCl3 = 6.91 g

Answer

n_AlCl3 = $\frac{m_{AlCl 3}}{M_{AlCl 3}}$ = $\frac{N}{N_{A}}$

⇒ m_AlCl3 = x M_AlCl3 = 6.91 g

Masses and mole number - 2 | The Periodic Table and Atoms