Hydrogen has an indigo emission line at 410.2 nm.
What is the energy and frequency of a photon of this light?

Question

| General Chemistry 1

Accepted Answer

E = hν = hc/λ

E =

\frac{6.626 \times 10^{- 34} \times 3.0 \times 10^{8}}{410.2 \times 10^{- 9}}

= 4.846 x 10^-19 J

c = λν ⇒ ν = c / λ = 7.314 x 10¹⁴ s^-1

Answer

E = hν = hc/λ

E = $\frac{6.626 \times 10^{- 34} \times 3.0 \times 10^{8}}{410.2 \times 10^{- 9}}$ = 4.846 x 10^-19 J

c = λν ⇒ ν = c / λ = 7.314 x 10¹⁴ s^-1

Wave model of light - 2 | Early Quantum Theory